z^2+2z+16=0

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Solution for z^2+2z+16=0 equation: 



z^2+2z+16=0

a = 1; b = 2; c = +16;
Δ = b2-4ac
Δ = 22-4·1·16
Δ = -60
Delta is less than zero, so there is no solution for the equation

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